Question

The ionisation energy of H atom is 13.6ev . It is exposed to electromagnetic waves of 1028 Angstrom and gives out induced radiation. Find the wavelength of these induced radiations.

Answer 1

Answer:

Explanation:

Hi,

Here is the answer to your question:

H-atom is exposed to UV radiation having wavelength 102.8nm

the energy of photon corresponding to 102.8 nm waveegth is

E = hc/λ = 1242 eV-nm /102.8 nm

= 12.42 eV

The energy needed to take athe H atom frm ground state to first excited state is

E2-E1 - 13.6 eV - 3.4 eV = 10.2 eV

and to the second excited state is

E3-E1 - 13.6 eV - 1.5 eV = 12.1 eV

and to the third excited state is

E4-E1 - 13.6 eV - 0.85 eV = 12.75 eV

thus 12.42 eV photon has large probability of being absorbed in 12.1 eV

The corresponding waveegth is: λ =103 nm