Question

the ionisation energy of h is 13.6 eV. what will be the ionisation energy for he and li

Answer 1

HEYA!!!


HERE IS YOUR ANSWER,


⇔ Well the Ionization Energy of He and Li would be :

SINCE,

⇔ IE = 13.6 × (Z² ÷ n²) eV


THEREFORE,

→ IE for He = 13.6 × (2² ÷ 1²) eV = 13.6 × 4 = 54.4 eV 

→ IE for Li = 13.6 × (3² ÷ 1²) eV = 13.6 × 9 = 122.4 eV 


THUS,

IE for He = 54.4 eV and IE for Li = 122.4 eV 


HOPE IT HELPS YOU,
THANK YOU. ^_^