Question

The ionisation energy of H is 1312 kJ mol-l. How much
energy is required to ionise 100 gram atoms of hydrogen?
[Ans. 6.56 x 10^4 kJ]​

Answer 1

Answer:

Ionisation energy is given for a mol of hydrogen = 1312 kJ/mol

therefore the Ionization energy for a single H-atom = 1312 /avogadro number

= 1312 /(6.02 . 10^23 atoms) = 2.18 .10^-18 kJ

this is ionisation energy for ground state atom ,for which the principal quantum number is n = 1

if the electron is in 2nd excited state its n = 3

so the ionisation energy for such an atom in 2nd excited state will be equal to the

= E (ground)/n^2 = 2.18 . 10 ^-18 / 9 = 2.42 . 10^ -19 J

or = 1.47 eV ( as 1 eV = 1.6 .10 ^-19 J)

Explanation:

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Answer 2

Ionisation Enthalpy for H atom = 1312 kJ/mol.

• We know that 2 gram atoms of hydrogen gas mean 1 mole of hydrogen gas.

• So, 100 gram atoms of Hydrogen gas = 50 moles of hydrogen gas.

So, total energy needed for ionisation:

$E = 1312 \times 50$

$\implies E = 65600 \: kJ$

$\implies E = 6.56 \times {10}^{4} \: kJ$

So, total energy needed is 6.56 × 10⁴ kJ.