Chemistry, asked by Helpneeded4968, 11 months ago

The ionisation enthalpy of hydrogen atom is 1.312*10^6 j/mol the energy required to excite electron from n=1 ton=2 is

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Answered by DreamBoy786
12

Answer:

Explanation:

Answer:

The different energy levels of a Hydrogen atom are given by the equation:

E = - E0/n2

where E0 = -1.312 KJ/mol  and n = 1,2,3… and so on.

For ground state n = 1

E1=E0/(1)2

So that the ground state has energy E1= -1.312 KJ/mol  

For first excited state n = 2  

So E2=-1.312 KJ/mol /4= -0.328 KJ/mole

Energy difference between two states:

        ΔE= E2-E1= (-0.328)-(-1.312)

                          = 0.984 KJ/mol

0.984 KJ/mol energy is required to excite an electron in hydrogen atom from ground to excited state.

Answered by mevadarajesh
1

Answer:

9.84×10^5J/mol

Explanation:

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