The ionisation enthalpy of hydrogen atom is 1.312*10^6 j/mol the energy required to excite electron from n=1 ton=2 is
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Explanation:
Answer:
The different energy levels of a Hydrogen atom are given by the equation:
E = - E0/n2
where E0 = -1.312 KJ/mol and n = 1,2,3… and so on.
For ground state n = 1
E1=E0/(1)2
So that the ground state has energy E1= -1.312 KJ/mol
For first excited state n = 2
So E2=-1.312 KJ/mol /4= -0.328 KJ/mole
Energy difference between two states:
ΔE= E2-E1= (-0.328)-(-1.312)
= 0.984 KJ/mol
0.984 KJ/mol energy is required to excite an electron in hydrogen atom from ground to excited state.
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Answer:
9.84×10^5J/mol
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