Question

the ionisation potential of a hydrogen atom is - 13.6 eV what will be the energy of the atom corresponding to n=2?​

Answer 1

According to the question, the Ionisation potential of hydrogen atom is 13.6eV.

Therefore, the change in energy involved in removing the electron from n=2 is given by

the formula E(n)=−13.6n2 eV/atom

However, in this case the electron is completely removed from n=2 , therefore

ΔE=E(∞)−E(2)

Therefore,

ΔE=0−(−13.622)

ΔE=+13.64

ΔE=3.4eV

Answer 2

Answer:

Energy for n=2 is -27.2ev

Explanation:

Energy for hydrogen like species (single electron species) is,

E= -13.6 Z^2/ n^2 ev