Question

The ionization constant of a weak electrolyte is 25×10^-6 while the equivalent conductance of its 0.01M solution is 19.6 S cm^2eq^-1 . The equivalent conductance of the electrolyte at infinite dilution will be

Answer 1

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Answer 2

Given : The ionization constant of a weak electrolyte is 25 × 10^-6 while the equivalent conductance of its 0.01M solution is 19.6 S cm² eq¯¹.

To find ; The equivalent conductance of the electrolyte at infinite dilution.

solution : we know, K = Cα²

⇒α = $\sqrt{\frac{K}{C}}$

here ionization constant, K = 25 × 10^-6

C = 0.01 M

so, α = $\sqrt{\frac{25\times10^{-6}}{0.01}}$

= 0.05

now equivalent conductance at infinite dilution,

$\Lambda_{eq}^{\infty}=\frac{\Lambda_{eq}}{\alpha}$

here, equivalent conductance, $\Lambda_{eq}$ = 19.6 S cm²eq¯¹

so, $\Lambda_{eq}^{\infty}=\frac{19.6}{0.05}$

= 392 S cm² eq¯¹

Therefore equivalent conductance of the electrolyte at infinite dilution is 392 S cm² eq¯¹