Question

The ionization constant of ammonium hydroxide is 1.77 into 25

Answer 1

HEY..

First off all ur question is incorrect bcoz ionization constant cannot be 1.77 bcoz the value of ionization constant is of order 10^-5, and even didn't mention the temprature. Though u can find hydrolysis constant by given formula

Kh = Kw / Kb

Thank you
HOPE IT HELPS..

Answer 2

Answer: 5.65×10∧-10

Explanation:

ionization constant = 1.77×10∧-5       --------( given)

we know that

hydrolysis constant = ionic product of water ÷ ionization constant of base

and ionic product of water = 10∧-14    ------( at 25°c)

so hydrolysis constant = 10∧-14 ÷ 1.77 × 10∧-5

                                       = 5.65 × 10∧-10