the ionization energy for lithium is 520kj/mol, calculate the amount of energy required to convert 140mg of lithium atoms in gaseous state into Li+ ion.
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The ionization energy tells us that for 1 mole of gaseous lithium,
520
k
J
of energy is needed to ionise each atom.
We also know that 1 mole contains
6.02
⋅
10
23
atoms (to
3
s.f.)
So, 1 atom =
1
6.02
⋅
10
23
=
6.02
⋅
10
−
23
m
o
l
520
k
J
=
520000
J
=
5.2
⋅
10
5
J
(
5.2
⋅
10
5
)
(
6.02
⋅
10
−
23
)
=
8.64
⋅
10
−
19
J
8.64
⋅
10
−
19
1.60
⋅
10
−
19
=
5.40
e
V
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