Question

The ionization energy of H atom is 13.6 eV. What will be ionization energy of He+ and Li+ ions?
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Answer 1

Answer:

Explanation:

To find the ionisation energy of a hydrogen like atom with one electron we use the formula

IE = 13.6Z²/n² eV

Where Z is atomic number and n is the shell number.

In this case Z is 3 and n is 1( because hydrogen is having n=1)

So IE of He+ = 13.6eV × 22 = 54.4eV

IE Li²+ = 13.6×9 = 122.4 eV.