Question

The ionization energy of He+ is 8.72x10^-18 J atom-1. Calculate the energy of the first stationary state of Li2+​
please answer

Answer 1

Explanation:

Use equation:

E=hcR(1/n1^2–1/n2^2)Z^2

where E is energy, c and R are constant, Z IS ATOMIC NUMBER

So for a particular transition in He(Z=4), Energy is 19.6x10^-18(say A),

the energy for the same transition in lithium(z=3) would be,

A*3^2/2^2=9A/4

so energy for Li+2 transition will be 9*19.6*10^-18/4=44.1*10^-18J per atom

Answer 2

Answer:

answer is 4.41×10power -18