Question

The ionization energy of Het is 19.6 x 10-18 J/atom. Calculate
the energy of the first stationary state of Be3+​

Answer 1

Answer:

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Explanation:

Use equation:

E=hcR(1/n1^2–1/n2^2)Z^2

where E is energy, c and R are constant, Z IS ATOMIC NUMBER

So for a particular transition in He(Z=4), Energy is 19.6x10^-18(say A),

the energy for the same transition in lithium(z=3) would be,

A*3^2/2^2=9A/4

so energy for Li+2 transition will be 9*19.6*10^-18/4=44.1*10^-18J per atom