Chemistry, asked by rishigattu116, 5 months ago


The ionization energy of hydrogen atom is 13.6 eV. Following Bohr's theory, the energy co
to a transition between the 3rd and the 4th orbit is
a) 3.40 eV
b) 1.51 eV
c) 0.85 eV
d) 0.66 eV​

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Answered by msjayasuriya4
1

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Chemistry

Structure of Atom

Development Leading to Bohr's Model of Atom

The work function for a met...

CHEMISTRY

The work function for a metal is 4 eV . To emit a photo electron of zero velocity from the surface of the metal, the wavelength of incident light should be:

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ANSWER

hv=hv

0

+KE for zero velocity KE=0

hv=hv

0

hv=4eV

λ

hc

=4eV

λ=

4eV

h×c

=

4×1.6×10

−19

6.626×10

−34

×3×10

8

=3100A

o

Hence, the correct option is D

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