Question

the ionization energy of hydrogen atom is 13.6 ev. the second ionisation energy would be

Answer 1

THERE WILL BE NO I.E2 IN H2 SINCE HYDROGEN HAS ONLY 1 ELECTRON WHICH  ALREADY EJECTED OUT BY APPLYING 13.6ev...

Answer 2

Explanation:

Ionization energy of hydrogen atom=−13.6Z

2

=−13.6eV

E

ionization

=

λ

hc

λ

ionisation

6.626×10

−34

×3×10

8

=13.6×1.6×10

−19

λ

ionisation

=912×10

−8

m

ionization energy for 1 mole H=E

ionization

×N

A

=13.6×1.6×10

−19

×6.023×10

23

=1310kJ/mole

=1313kJ/mol(approx)