The ionization energy of hydrogen atom is 13.6 ev what will be the ionization energy of helium and lithium ion
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ionization energy proportion to Z²/n² then for
He energy is 13.6 ×2²=13.6×4=54.4ev
and for Li it is 13.6×3²= 13.6×9= 122 .4ev
He energy is 13.6 ×2²=13.6×4=54.4ev
and for Li it is 13.6×3²= 13.6×9= 122 .4ev
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