Question

The ionization energy of hydrogen atom is 13.6 v calcuate the energy in first excited state

Answer 1

Explanation:

Ionization energy of hydrogen atom=−13.6Z

2

=−13.6eV

E

ionization

=

λ

hc

λ

ionisation

6.626×10

−34

×3×10

8

=13.6×1.6×10

−19

λ

ionisation

=912×10

−8

m

ionization energy for 1 mole H=E

ionization

×N

A

=13.6×1.6×10

−19

×6.023×10

23

=1310kJ/mole

=1313kJ/mol(approx)