Question

The ionization energy of hydrogen is 13.6 then find the first and second ionization of helium

Answer 1

Hi frnd

ANSWER
The first ionization energy of H to H
+
is 13.6 eV.
The first ionization energy of He to He
+
is 24.6 eV......(1)
When a He
2+
ion accepts an electron, the energy released is Z
2
=2
2
=4 times the first ionization energy of hydrogen atom.
Thus, the energy for the ionization of He
2+
to He
+
is 4×13.6=54.4eV......(2)
When (1) and (2) are added, we get the energy given out when He
2+
ion gains 2 electrons and forms He atom in its ground state.
It will be 24.6eV+54.4eV=79eV.

Hope this helps u

Answer 2

Answer:

The first ionization energy of H to H

+

is 13.6 eV.

The first ionization energy of He to He

+

is 24.6 eV......(1)

When a He

2+

ion accepts an electron, the energy released is Z

2

=2

2

=4 times the first ionization energy of hydrogen atom.

Thus, the energy for the ionization of He

2+

to He

+

is 4×13.6=54.4eV......(2)

When (1) and (2) are added, we get the energy given out when He

2+

ion gains 2 electrons and forms He atom in its ground state.

It will be 24.6eV+54.4eV=79eV.