Question

The ionization energy of the ground state of hydrogen atom is 2.18 x 10-18J. The energy of an electron in its second orbit would be A)1.10 x 10-18 J B)-2.18 x 10-18 J C)-4.36 x 10-18 J D)-5.45 x 10-19 J

Answer 1

Answer:

heya here is the answwer

Explanation:

The ionization energy is given to be =2.18×10

−18J, which equals 13.6eV. Therefore, the energy of electron in the first level is −13.6eV. We can thus use the formula, E=−13.6×Z 2/n 2 to calculate energy of electron in the second orbit.

E 2= 2 2−2.18×10 −18

=−5.45×10 −19 J

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Answer 2

-0.545×10↑-18

Explanation:

this is the answer i hope i am right pls mark me brainliest and rate my answer too