Question

The ionization energy of the hydrogen atom is 13.6 ev. what is the energy of the n = 5 state

Answer 1

0.544 is energy in 5 state
E = 13.6/n*n
n = state of electron

Answer 2

Answer:

Total energy of electron in n=2 state E

n

=

n

2

−13.6

where n=2

∴ E

2

=

2

2

−13.6

=−3.4eV

Thus potential energy of electron U

2

=2E

2

⟹ U

2

=2(−3.4)=−6.8eV