The ionization enthalpy of hydrogen atom is
1.313 106 J mol-1. The energy required to excite the
electron in the atom from n = 1 to n = 2 is
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Answers
Answered by
0
Answer:
Energy of electron in first orbit =E
1
=−1312 kJ/mol
Energy of electron in secondorbit =E
2
=−
2
2
1312
=−328 kJ/mol
Hence, Energy required to excite a hydrogen electron from n=1 to n=2 =E
2
−E
1
=−328−(−1312)=984 kJ/mol
Hence B is the correct answer
Explanation:
Answered by
1
Answer:
The Energy of an electron in the first orbit = E
1 = − 1.312 × 10^6 J/mol
The Energy of electron in second orbit = E2 = − 1.312 × 10^6 J (1 /2^2)
= − 1.312 × 10^6 J * 1/4
= − 3.28 × 10^5 J
∴ ΔE = E2 - E1 = − 3.28 × 10^5 J − (− 1.312 × 10^6)
= 9.84 × 10^5 J /mol
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