Question

the ionization enthalpy of hydrogen is 1312.0 kj mol-¹ express the value in eV per atom using the relation 1eV =1.602×10^-19j i m again posting this question plzzz don't give bakwaas answers ​

Answer 1

Explanation:

energy of electron in first orbit =E

1

=−1312 kJ/mol

Energy of electron in secondorbit =E

2

=−

2

2

1312

=−328 kJ/mol

Hence, Energy required to excite a hydrogen electron from n=1 to n=2 =E

2

−E

1

=−328−(−1312)=984 kJ/mol