Question

The ionization of hydrogen atom is 13.6 eV.
The energy corresponding to a transition
between 3rd and 4th orbit is ......​

Answer 1

Answer:

0.66 eV.

Explanation:

According to Bohr's theory,

E

n

=

n

2

−13.6

∴E

3

=

3

2

−13.6

=

9

−13.6

=−1.51eV

E

4

=

4

2

−13.6

=

16

−13.6

=−0.85eV

Energy corresponding to a transition between the 3

rd

and 4

th

orbit =E

4

−E

3

=−0.85−(−1.51)=0.66eV

Hence, the energy corresponding to a transition between the 3

rd

and 4

th

orbit is 0.66eV.