Question

The ionization potential for the electron in the ground state of the hydrogen atom is 13.6 eV atom". the ratio of ionisation potential for the electron in the 1st excited state of He+ to the electron in 2nd excited state of li2+​

Answer 1

Answer:

1

Explanation:

Energy = - 13.6(z^2)/n^2 & ionisation energy is equal to - (E)

thus (I.E)He+;n→2 = 13.6(2^2)/2^2 &

for Li2+ {z=3 & n=3} = 13.6(3^2)/3^2

on taking ratio we will get ratio as 1