The ionization potential of hydrogen atom is 13.6 ev . Calculate the speed of electron which could just ionized the hydrogen atom
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ionisation potential of hydrogen atom, I.P = 13.6 volts
so, ionisation energy , I.E = charge on electron × I.P
= 13.6 eV
= 13.6 × 1.6 × 10^-19 Joule
= 2.176 × 10^-18 Joule
as you know, ionisation energy is amount of energy required to remove an electron from an isolated gaseous atom.
Let speed of electron = v which could just ionized the hydrogen atom.
so, kinetic energy = ionisation energy
or, 1/2 mv² = 2.176 × 10^-18
or, 1/2 × 9.1 × 10^-31 × v² = 2.176 × 10^-18 [ mass of electron is 9.1 × 10^-31 kg ]
or, 4.55 v² = 2.176 × 10¹³
or, v² = (21.76/4.55) × 10¹²
or, v² = 4.78 × 10¹²
or, v = 2.18 × 10^6 m/s
hence, speed of electron is 2.18 × 10^6 m/s
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