Question

The iron door of a building is 3m broad. It can be opened by applying a force of 100N normally at the middle of the door. Calculate: - a) The torque needed to open the door.

Answer 1

Answer: moment of force needed =

Force * perpendicular distance

Explanation:

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Answer 2

Answer:

The torque needed to open the iron door is 150Nm.

Explanation:

The torque in terms of force is given as,

$\tau=r\times F$               (1)

Where,

τ=torque acting on an object

r=distance of the point from the point of application of force

F=force acting on the object

From the question we have,

F=100N

Distance of the middle of the door from point of application of force is given as,

$r=\frac{3}{2}$          (2)

By putting the value of r and force in equation (1) we get;

$\tau=\frac{3}{2}\times 100=150Nm$

Hence, the torque needed to open the door is 150Nm.