Question

The iron gate of a building is 3m broad. It can be opened by applying 100N
force at the middle of the iron gate. Calculate the least force required to open
this gate. Where should it be applied?

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Answer 1

Answer:

The iron door of a building is 3m broad. It can be opened by applying a force 100N normally at the middle of the door. Calculate: ja ...

Answer 2

Explanation:

The force applied at the middle of gate= 100N

The distance of gate from hinge = 3m

The distance at which the 100 Newton of force is applied = 3/2 = 1.5 m

The maximum force will be required if the force is applied at the free end of the gate= 3m

Thus , by principle of moments

F1 × D1 = F2 × D2

100 × 1.5 = F2 × 3

Thus , F2 = ( 100 × 1.5 ) / 3 = 50N

1. Thus , least force which can open the door is 50N

2. The force has to be applied at the distance of 3m from the hinge of the gate to the open the gate with least force.

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