Math, asked by suman1277, 11 months ago

the irrduciable factorisation 0f (121x^2-169y^2

Answers

Answered by aaravshrivastwa
5
Here,

=> (121x^2-169y^2)

=> {(11x)^2-(13y)^2}

As we know that,

=> a^2-b^2 = (a+b)(a-b)

=> (11x)^2 - (13y)^2 = (11x + 13y) (11x - 13y)




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Answered by sandykamboj03
2

Step-by-step explanation:

(121x^ - 169y^ = (11x^ - (13y^)

= (11x+13y) (11x-13y)

= (: a^-b^ = ( a+b )

here, irreducile factorization of = (121x^-169y^)

= (11x^ + 13y) (11x-13y

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