Question

The irreducible factorisation of 63z²y³x is ______.
(A) 9z²y³x
(B) 9z²×7y²×2x
(C) 9z²×7x×y²
(D) 3z²×7x×3y³​

Answer 1

Answer:

3z²×7x×3y³

Step-by-step explanation:

63z²y³x= 3z²×7x×3y³

Answer 2

Below is the description of the factorization, which is defined in the question.

Step-by-step explanation:

$\ The \ value \ is \ given \ that:$ $63z^2y^3x$

$\ When \ we \ calculate \ the \ L.C.M \ of \ 63 \ it \ will \ give$ $: 3 \times 3 \times 7 \ that \ is \ equal \ to \ 63$$\ and \ the \ variable \ value \ is \ same, \ that's \ why \ the \ option D \ is \ the \ correct\\ ,\ and \ other \ options \ were \ wrong.$

$63= (9)\times 7= 3 \times 3 \times 7.$

$Z^2= z \times z$

$y^3= y \times y \times y$, and

x=x.

that's why $3 z^2\times7x\times3y^3$ is the correct answer.

Learn more:

• Factorise: https://brainly.in/question/4565571
• Prime factorisation​: https://brainly.in/question/9355249