Math, asked by nashdonaker, 1 month ago

The isosceles trapezoid has a height of 4 and bases 7 and 17. Find the length of the leg.

Answers

Answered by shreyarajput1188
2

Answer:

here

Step-by-step explanation:

First find the average length of the 2 bases: avg. = (8 + 16)/2 = 12. To find the area, multiply this result

The 13cm diagonal is the hypotenuse, and the 12cm base segment is one leg, meaning that the other leg(altitude) must have a length of a^2 = 13^2 — 12^2 = 25 (pythagorean theorem), so a=5cm. The area of the trapezoid = 5cm*12cm = 60cm^2

I hope you like it

Answered by Anonymous
10

Answer:

Additionally, an isosceles trapezoid must have two nonparallel sides that have equivalent lengths. Therefore, use the given information to apply the formula: Perimeter= Base one Base two (leg), where the length of "leg" is one of the two equivalent nonparallel sides.

To find the area of a trapezoid, multiply the sum of the bases (the parallel sides) by the height (the perpendicular distance between the bases), and then divide by 2.

Step-by-step explanation:

Hope my answer helped you !

Please mark as brainlist !

Have a wonderful day tomorrow!

Similar questions