The IUPAC name for
C1
|
CH₃–C–CH₂–CH–CH–CH₃ is
|
H
(a) 5–chlorohex–2–ene
(b) 2–chlorohex–5–ene
(c) 1–chloro–1–methylpent–3–ene
(d) 5–chloro–5–methylpent–2–ene
Answers
Answered by
5
Answer:
The IUPAC name for
C1
|
CH₃–C–CH₂–CH–CH–CH₃ is
|
H
(a) 5–chlorohex–2–ene
(b) 2–chlorohex–5–ene
(c) 1–chloro–1–methylpent–3–ene
(d) 5–chloro–5–methylpent–2–ene✔✔
Answered by
0
Option (a)
5-chlorohex -2 -ene.
Explanation:
Cl
6 |5 4 3 2 1
CH₃ - C - CH₂ - CH=CH - CH₃
|
H
Here present 6 Carbons for this it is a hex.
In 5th carbon there exist a chlorine molecule.
And a double bond is contained by 2nd carbon.
IUPAC rules:
- We have to find out longest continuous carbon change.
- 1 carbon = meth, 2 carbon= eth , 3 carbon= prop, 4 carbon = but,5 carbon= pent, 6 carbon = hex.
- F= fluoro, Cl =chloro, Br = bromo
- when double bond present = ene.
Therefore it is 5-chlorohex -2 -ene.
Similar questions