Chemistry, asked by udayk9069, 11 months ago

The IUPAC name for
C1
|
CH₃–C–CH₂–CH–CH–CH₃ is
|
H
(a) 5–chlorohex–2–ene
(b) 2–chlorohex–5–ene
(c) 1–chloro–1–methylpent–3–ene
(d) 5–chloro–5–methylpent–2–ene

Answers

Answered by yogichaudhary
5

Answer:

The IUPAC name for

C1

|

CH₃–C–CH₂–CH–CH–CH₃ is

|

H

(a) 5–chlorohex–2–ene

(b) 2–chlorohex–5–ene

(c) 1–chloro–1–methylpent–3–ene

(d) 5–chloro–5–methylpent–2–ene✔✔

Answered by jitendra420156
0

Option (a)

5-chlorohex -2 -ene.

Explanation:

           Cl  

6           |5       4     3       2     1

CH₃  -  C  -   CH₂ - CH=CH -  CH₃

            |

            H

Here present  6 Carbons for this it is a hex.

In 5th carbon there exist a chlorine molecule.

And a double bond is contained by 2nd carbon.

IUPAC rules:

  • We have to find out longest continuous carbon change.
  • 1 carbon = meth, 2 carbon= eth , 3 carbon= prop, 4 carbon = but,5 carbon= pent, 6 carbon = hex.
  • F= fluoro, Cl =chloro, Br = bromo
  • when double bond present = ene.

Therefore it is 5-chlorohex -2 -ene.

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