Question

The IUPAC name of the compound
0:
H2C—C—CH – CH – COOH
is_
CI
Br
AO 2-bromo-3-chloro-4-oxopentanoic acid
B.O 4-oxo-3-chloro-2-bromopentanoic acid
C.O 3-carboxy-2-bromo-3-chlorobutanone
DO 3-chloro-2-bromo-4-oxopentanoic acid​

Answer 1

Answer:

The following steps are taken into account for naming the compound;

i) The parent chain consists of five carbon atoms and the primary functional group is carboxylic acid, thus the suffix -oic acid.

ii) CO is the secondary functional group, thus the prefix -oxo is used for it.

iii) Br and Cl are the substituents for which prefix bromo and chloro are used respectively.

iv) CO, Br, Cl are written in alphabetical order.

Thus the name of the compound is; 2-bromo-3-chloro-4-oxopentanoic acid.