Chemistry, asked by samsingh2004, 3 months ago

The IUPAC name of the following compound is
(A)2-Nitro-6-methlhepta-2,5-dienoic acid
(B) 1-Hydroxy-6-Methyl-2-nitrohepta-2.5-dienone
(C) 6-Methyl-2-nitro-1-Hydroxyhepta-2,5-dienone
(D)6-methyl-2-Nitohepta-2.5-dienoic acid

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Answered by Anonymous
2

The correct answer will be (A) 6-Methyl-2-nitrohepta-2,5-dienoic acid.

The numbering for the compound will begin from the carboxyl group, the longest carbon chain in this manner will have seven carbon atoms.

So, the root word will be hepta.

The double bonds are found at positions 2 and 5.

So, it will be hepta-2,5-dienoic acid .

Apart from that, the nitro group is attached at 2nd and the methyl group is attached at 6th carbon atom.

Nitro comes first followed by methyl according to alphabetical order.

So, the complete IUPAC name will be:

2-Nitro-6-methylhepta-2,5-dienoic acid.

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