The K.E of 4moles of nitrogen gas at 127 degree celcius is .......... cal ?
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Answer:According to Kinetic theory of gases, Kinetic Energy of a gas at given temperature is
K.E.=32nRT
Where
nRT=no. of moles of gas=Universal gas constant=Temperature(K)
Therefore, Kinetic Energy of 4 moles of Nitrogen gas at 127°C(400K) will be
K.E.=32×4×8.314×400=19953.6J
NOTE : In this all, I have assumed that nitrogen behaves as an ideal gas
Explanation:
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