Question

.The K.E of a body is 3J and its M.I is 6 kg m2
.Then its angular momentum will be

Answer 1

Given:

The K.E of a body is 3 J and its M.I is 6 kgm².

To find:

Angular Momentum ?

Calculation:

$KE = \dfrac{1}{2} \times I \times { \omega}^{2}$

$\implies 3= \dfrac{1}{2} \times 6\times { \omega}^{2}$

$\implies 3= 3\times { \omega}^{2}$

$\implies { \omega}^{2} = 1$

$\implies \omega = 1 \: rad {s}^{ - 1}$

Now, angular momentum is :

$L = I \times \omega$

$\implies L = 6\times 1$

$\implies L = 6 \: kg {m}^{2} {s}^{ - 1}$

So, angular momentum is 6 kgm²/s.

Answer 2

Given:-

The K.E of a body is 3 J and its M.I is 6 kgm².

To Find:-

Angular Momentum ?

Calculation:-

K.E.=1/2×I×ω²

⇒3=1/2×6×ω²

⇒3=3×ω²

⇒ω²=1

⇒ω = 1 rads−¹

Now, angular momentum is :

L=I×ω

⇒L=6×1

⇒L=6 Kgm²s−¹

So, angular momentum is 6 kgm²/s.

☆Hope it helps you☆