Question

The K.E. of a moving body becomes four times the original f the velocity is doubled.Verify it Numerically​

Answer 1

Explanation:

$kinetic \: energy = \frac{1}{2} m {v}^{2} \\ \\ if \: \: \: \: \: \: v = 2 {u}^{} \\ \\ then \: \: \: \: \: \: final \: \: \: \: \: \: \: kinetic \: energy = \frac{1}{2} m {u}^{2} {2}^{2} = 4 \times initial \: kinetic \: energy..$