THE K.E OF A MOVING BODY IS 250 J
IF THE VELOCITY OF A BODY INCREASED BY 5 TIMES FIND IT NEW K.E
Answers
K.E₁ = 250J
velocity = v
mass = m
K.E₁ = (1/2)mv²
if the velocity is increased by 5times, what is it's new K.E [K.E₂ = ? ]
new velocity = 5v
and mass is unchanged.
mass = m
so,
⇒ K.E₂ = (½) m (5v)²
⇒ K.E₂ = (½)(m)(25v²)
⇒ K.E₂ = (½mv²)(25)
⇒ K.E₂ = 25(250)
⇒ K.E₂ = 6250J
It's New Kinetic Energy is 6250J .
Answer :-
New kinetic energy of the body is 6250 Joules .
Explanation :-
We have :-
→ Kinetic energy of the body = 250 J
→ Increase in velocity (v') = 5 times
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If we consider the first situation, then we get it's equation as :-
⇒ ½mv² = K.E.
⇒ ½mv² = 250 ----(1)
Now, velocity is increased by 5 times i.e. v' = 5v So the equation for new kinetic energy (K.E.') will be :-
⇒ ½m(v')² = K.E.'
⇒ ½m(5v)² = K.E.'
⇒ 25mv² = 2K.E.' ---(2)
On dividing eq(2) by eq(1), we get :-
⇒ 25mv²/(½mv²) = 2K.E.'/250
⇒ 50 = 2K.E.'/250
⇒ 2K.E.' = 12500
⇒ K.E.' = 12500/2
⇒ K.E.' = 6250 J