Question

. The K.E of a projectile at the highest point of its trajectory is 75% of its K.E. at the
point of projection. The angle of projection ​

Answer 1

Answer:

30°

Explanation:

The kinetic energy of a projectile at the highest point of its path is found to be 3/4th of its initial

At highest point of any projectile, the vertical component of its velocity has decayed to zero. Therefore, its only velocity at that point is its horizontal component (and the kinetic energy will be at the minimum value of its flight).