Chemistry, asked by pratik6465, 1 year ago

The K, for the dissociation of 2HI(g) = H2(g)+2 (B) is 1.84 x 10-2. If the equilibrium
concentration of H, is 0.4789 mole/lit, then the equilibrium concentration of HI is (in M)
(A) 8.52
(B) 6.2
(C) 5.1
(D) 3.5​

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Answered by likit93
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Answer:

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