The Kβ X-ray of argon has a wavelength of 0.36 nm. The minimum energy needed to ionize an argon atom is 16 eV. Find the energy needed to knock out an electron from the K shell of an argon atom.
Answers
Answered by
0
The energy required to strike an electron from the argon atom’s K shell is 3.47 keV approximately.
EXPLANATION:
It is given in this question:
- Kβ X-ray of argon’s wavelength, λ = 0.36 nm
- To ionise an argon atom, the required energy = 16 eV
- Kβ X-ray of argon’s energy, E is shown as
- E = 12420.36 =3450 eV
- To strike an electron from K shell, required energy is EK = (3450 + 16) eV
- EK = 3466 eV, which is approximately 3.47 keV
Similar questions