Question

The Kβ X-rays from certain elements are given below. Draw a Moseley-type plot of √v versus Z for Kβ radiation. Element
Ne
P
Ca
Mn
Zn
Br
Energy (keV)
0.858
2.14
4.02
6.51
9.57
13.3

Answer 1

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Answer 2

Explanation:

The value of v can be obtained directly using energy frequency relation,

hv = energy

where, h = Constant of Planck

v = Energy (in keV) / h

The graph is shown in below:  

When e jumps to n = 1 from n = 3, KB radiation happens.  

 $\Delta E=h v=R h c(z-h)^{2}\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)$

$\Rightarrow \sqrt{v}=\sqrt{\frac{9 R C}{8}}(z-h)$

Therefore, √v is proportional to z.

We need to find this √v and the above graph denotes the same. Here, n is the principal quantum number.