The Karl Pearson's coefficient of correlation in between two variables X and Y is 1, covariance of X and Y is 6 and variance of X is 9 then what is the value of standard deviation of Y?
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standard deviation of Y = 2
Step-by-step explanation:
Karl pearson's correlation coefficient is given by,
r = cov(X,Y)/(sigma X × sigma Y)
here Cov (X,Y) = 6,
variance of X = 9,
⇒ sigma X = √9
= 3
and r = 1
substituting the values, we will get
1 = 6/(3* sigma Y)
⇒ (3*sigma Y) = 6
⇒ sigma Y = 6/3
= 2
therefore sigma Y is 2
sigma Y is the standard deviation
∴ standard deviation of Y = 2
variance of Y = 2^2 (∵ variance = (SD)^2 )
variance of Y = 4
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