Question

the KE of an electron in the 2nd orbit of H atom is​

Answer 1

K.E. of H atom in Ist orbit is 13.6ev/atom.

K.E. at nth orbital is,

$= 13.6 \times \frac{ {z}^{2} }{ {n}^{2} }$

so K.E. in 2nd orbit,

$= 13.6 \times \frac{1}{ {2}^{2} }$

$= 3.4$