Question

The kinetic energy K of a particle of mass m moving with a speed vis
K = (1/2)mv2. A particle with mass 10 grams has, at a certain moment,
velocity 30 centimeters per second. At what rate is the kinetic energy chang-
ing?​

Answer 1

Step-by-step explanation:

Change in kinetic energy wrt time

$\frac{d}{dt} k = \frac{d}{dt}( \frac{1}{2} m {v}^{2} ) = \frac{2mv}{2} \frac{dv}{dt} = mva$