The kinetic energy (KE) of a motorcycle of mass (m) 95 kg (correct to 10 kgs) traveling at an average velocity (v) of 20 ms-1 (correct to 1 ms-1) is given by
KE = 1 / 2 mv2.
Calculate the range of the upper and lower bounds of the kinetic energy of the motorcycle.
________ joules ≤ KE < ________joules.
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Simplify the given expression. (5+√7) (2+√5)
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