the kinetic energy of a 0.5kg stone is 100J the momentum of the stone is
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Answer:
Given : h=40 m m=2kg u=0m/s
Force due to air resistance f=20N
Acceleration of the stone a=g−
m
f
=10−
2
20
=0 m/s
2
Using v
2
−u
2
=2aS
∴ v
2
−0=2(0)×40 ⟹v=0m/s
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