the kinetic energy of a body decreases by 19 percent what is the percentage decrease in its linear momentum
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KE = mv^2/2
=(mv)^2/2m
=P^2/2m
Therefore KE is directly proportional to P^2
New KE = KE*81/100
New P = ✓KE*81/100
=P *9/10
So percent decrease in linear momentum is 10%
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