Question

The kinetic energy of a body is numerically equal to thrice the momentum of the body. Find the velocity of the body.

Answer 1

hi buddy
here's your answer looking for

★KE ★↓
$\frac{1}{2} m {v}^{2}$
and,

★MOMENTUM★ ↓

$mv$
So,

according to the Question

$= > \: 3( \frac{1}{2} m {v}^{2} ) = mv \\ \\ = > \frac{3}{2}m {v}^{2} = mv \\ \\ = > v = \frac{2}{3} = 0.66m{s}^{ - 1}$
hope you are satisfied with my answer

Answer 2

Let, velocity = v

Mass = m

∴ KE = $\dfrac{1}{2} mv^2$

& Momentum = $mv$.

As per Question, the numerical value of KE is equal to thrice of momentum.

∴ KE = 3p

⇒ $\dfrac{1}{2} mv^2 = 3mv$

⇒ $\dfrac{1}{2} v = 3$

⇒ $v = 3 \times 2$

⇒ $v = 6 \ ms^{-1}$.

∴ Velocity of the body was of 6 m/s.