Question

the kinetic energy of a body of mass 2 kg and momentum of 200 m per second is

Answer 1

K.E=P^2/2m

K.E= (200)^2 /2×2

K.E= 40000/4=10,000J

Answer 2

kinetic energy =
$\frac{1}{2} m{v}^{2}$
1/2 × 2 × 200
=1/2 × 400
=200