The kinetic energy of a body of mass 2 kg moving with a velocity of 2m/s second is....
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Answer:Initial kinetic energy
Ki = 1/2 m v^2 = 1/2×2×4= 4 J
Final kinetic energy
Kf = 1/2×2×16 = 16 J
% change in KE
=(Kf - Ki)/Ki ×100
= (16-4)/4 ×100
= 3×100= 300%
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