Question

the kinetic energy of a body of mass 500g is 1250j .find its speed​

Answer 1

$\huge{\underline{\underline{\textbf{\green{Answer}}}}}$

v = 30√26 ${m}{s}^{-1}$

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Given:

• Mass of body, m = 500 g = 0.5 kg
• Kinetic Energy, k = 1250 J

Now,

$k = \frac{1}{2} m {v}^{2} \\ \\ 1250 = \frac{1}{2} \times 0.5 \times {v}^{2} \\ \\ {v}^{2} = \frac{1250 \times 2}{0.5} \\ \\ {v}^{2} = \frac{1250 \times 2 \times 10}{5} \\ \\ {v}^{2} = 1250 \times 4 \\ \\ {v}^{2} = 9000 \\ \\ v = \sqrt{9000} \\ \\ v = \sqrt{2 \times 2 \times 2 \times 3 \times 3 \times 5 \times 5 \times 13 } \\ \\ v = 2 \times 3 \times 5 \sqrt{26} \\ \\ v = 30 \sqrt{26} \: m {s}^{ - 1}$

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Answer 2

Answer:

v = 30√26 {m}{s}^{-1}ms

−1

_________________________

Given:

Mass of body, m = 500 g = 0.5 kg

Kinetic Energy, k = 1250 J

Now,

\begin{lgathered}k = \frac{1}{2} m {v}^{2} \\ \\ 1250 = \frac{1}{2} \times 0.5 \times {v}^{2} \\ \\ {v}^{2} = \frac{1250 \times 2}{0.5} \\ \\ {v}^{2} = \frac{1250 \times 2 \times 10}{5} \\ \\ {v}^{2} = 1250 \times 4 \\ \\ {v}^{2} = 9000 \\ \\ v = \sqrt{9000} \\ \\ v = \sqrt{2 \times 2 \times 2 \times 3 \times 3 \times 5 \times 5 \times 13 } \\ \\ v = 2 \times 3 \times 5 \sqrt{26} \\ \\ v = 30 \sqrt{26} \: m {s}^{ - 1}\end{lgathered}

k=

2

1

mv

2

1250=

2

1

×0.5×v

2

v

2

=

0.5

1250×2

v

2

=

5

1250×2×10

v

2

=1250×4

v

2

=9000

v=

9000

v=

2×2×2×3×3×5×5×13

v=2×3×5

26

v=30

26

ms

−1

hppe ots help you