Question

The kinetic energy of a bullet of mass 0.5kg fired from a gun moving with a velocity of 2ms-1 is

Answer 1

Explanation:

0.5 kg = 500g

KINETIC ENERGY = 1/2 *mv^2

= 1/2 × 500 ×2

= 500 J

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Answer 2

GiveN :

• Mass of Bullet (m) = 0.5 kg
• Velocity of bullet (v) = 2 m/s

To FinD :

• Kinetic Energy of Bullet

Solution :

Use formula for the Kinetic Energy :

$\leadsto \boxed{\sf{K.E \: = \: \dfrac{1}{2} mv^2}} \\ \\ \implies {\rm{K.E \: = \: \dfrac{1}{2} \: \times \: 0.5 \: \times \: 2^2}} \\ \\ \implies {\rm{K.E \: = \: \dfrac{1}{2} \: \times \: 0.5 \: \times \: 4}} \\ \\ \implies \rm{K.E \: = \: \dfrac{2}{2}} \\ \\ \implies \rm{K.E \: = \: 1} \\ \\ \underline{\sf{\therefore \: Kinetic \: Energy \: of \: bullet \: is \: 1 \: J}}$

• Energy : Energy is defined as the capacity to do work.

• Types of Energy : There are various types of energies, such as wind energy, electrical energy, kinetic energy, potential energy, etc.

• Unit of Energy : S.I unit of Energy is Joule (J). And other units are calories and ergs.